2.7t^2-30t+5.5=0

Solution for 2.7t^2-30t+5.5=0 equation:

2.7t^2-30t+5.5=0

a = 2.7; b = -30; c = +5.5;
Δ = b2-4ac
Δ = -302-4·2.7·5.5
Δ = 840.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-\sqrt{840.6}}{2*2.7}=\frac{30-\sqrt{840.6}}{5.4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+\sqrt{840.6}}{2*2.7}=\frac{30+\sqrt{840.6}}{5.4}
$